結果 : y is equal to tan inverse 1 cos x sin x
2:44

If `y = tan^(-1) ((1 - cos x)/(sin x)) " then "(dy)/(dx)=` ?

Doubtnut
7,141 回視聴 - 4 年前
4:28

If ` y = tan^(-1)((cos x)/(1 + sin x)), "then" (dy)/(dx) ` is equal to

Doubtnut
3,037 回視聴 - 4 年前
2:41

Differentiate tan ^(-1)⁡ ((1+cos⁡x)/sin⁡x ) with respect to x | tan inverse 1 + cos x by sin x

SARAL INSTITUTE
2,740 回視聴 - 1 年前
1:27

If `y=tan^(- 1)((1+cosx)/(sinx)),then(dy)/(dx)=`

Doubtnut
9,010 回視聴 - 6 年前

-
2:06

y=`tan^(-1)((sinx)/(1+cosx))` Find dy/dx

Doubtnut
10,550 回視聴 - 4 年前
22:47

Evaluating Inverse Trigonometric Functions

The Organic Chemistry Tutor
1,339,890 回視聴 - 3 年前
1:47

If y=tan^-1 (cos x/1+ sin x) then.Find dy/dx=? It's come in cbse board exam two times #class12#cbse

IQ LEVEL SOLUTIONS
384 回視聴 - 1 年前

-
10:33

Differentiate tan^-1((1+cosx)/sinx)) then dy/dx / tan inverse((1+cosx)/sinx)) / Differentiation

Excellent Ideas in Education
1,664 回視聴 - 1 年前
1:36:19

Calculus 1 Exam Review Part 2

Calculus Problems and Solutions
355 回視聴 - 3 日前 に配信済み
2:34

If `y = tan^(-1){(cos x + sinx)/(cos x - sin x)} " then " (dy)/(dx) =` ?

Doubtnut
4,579 回視聴 - 4 年前
4:07

tan inverse (cosx/1-sinx) |solution of inverse trigonometric function class- 12

Fearless Force
55,345 回視聴 - 4 年前
2:40

Q13 | Differentiate tan^(-1)⁡(cos⁡x/(1+sin⁡x ))

GRAVITY COACHING INSTITUTE
1,332 回視聴 - 5 年前
2:24

Q5 | Write in the simplest form:- tan^(-1)⁡((cos⁡x-sin⁡x)/(cos⁡x+sin⁡x)) | Inverse Trigonometric Fun

GRAVITY COACHING INSTITUTE
11,614 回視聴 - 4 年前
6:06

If y = tan⁻¹(cosx + sinx / cosx - sinx) then Find dy/dx

Pace Edu.
214 回視聴 - 1 年前
3:17

Find the derivative of `tan^(- 1)[(cosx)/(1+sinx)]` wrt `x`

Doubtnut
19,325 回視聴 - 6 年前
11:53

if y=tan^(-1) [(1-cosx)/sinx] find dy/dx If y = tan^(-1)[cosx/(1-sinx)] find dy/dx Differential

DeVa Singh_7
310 回視聴 - 3 年前
1:59

If `y=tan^(-1)((1-cosx)/(sinx)),` then `(dy)/(dx)` is

Doubtnut
2,873 回視聴 - 4 年前
7:15

If y = tan⁻¹[ cosx/(1 + sinx)] , Find dy/dx

Pace Edu.
148 回視聴 - 1 年前
3:46

Differentiate tan ^(-1)⁡((cos⁡x-sin⁡x)/(cos⁡x+sin⁡x )) with respect to x | tan inverse cosx -sinx /

SARAL INSTITUTE
1,920 回視聴 - 1 年前
1:44

`tan^(-1)((cosx+sinx)/(cos x-sinx))`

Doubtnut
13,599 回視聴 - 4 年前