3x^3-2x^2-12x+8=0の解き方
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2 乗因数分解を使用した多項式の 4 乗因数分解
Solve x^4+〖2x〗^3-7x^2-8x+12=0
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多項式 x^3 - 6x^2 + 12x - 8 のすべての有理零点を求めます。
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Factorise 3x3 – 2x2 – 12x + 8 = 0
If the polynomial x4+2x3+8x2+12x+18 is divided by another polynomial x2+5 the remainder comes out to
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Find points on the curve y= 2x^3 + 3x^2 -12x + 1 where the tangent is horizontal
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