`(2x+4y+3)(dy)/(dx)=2y+x+1`
Q96 (2x+4y+3)(dy/dx) = 2y+x+1
微積分ヘルプ: 微分方程式 - リダクション変数 - (2x+4y+3) dy/dx=x+2y+1
`(x+2y +1) dx - (2x + 4y +3)dy = 0, x+2y = u`
(2x + y + 3) dx = (2y + x + 1) dy , Solve Non-Homogenous Differential Eq'n @EAG
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Solve : (2x-4y+5)dy+(x-2y+3)dx=0
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#21 ||問題 #3 を解く: (𝒅^𝟐 𝒚)/〖𝒅𝒙〗^𝟐 −𝟒𝒚=𝒄𝒐𝒔𝒉(𝟐𝒙−𝟏)+𝟑^𝒙 || 18MAT21 ||
陰的微分 3x^2 + 2xy + 4y^2 微積分 MCV4U