二項式の3乗を展開する方法

【高校　数学Ⅱ】　式と証明１　３乗の展開公式　（１５分）

The term independent of x in expansion of ((x+1)/(x^(2/3)-x^(1/3)+1)-(x-1)/(x-x^(1/2) ))^10 is

The number of integral terms in the expansion of (〖3^(1/2)〗_ ^ + 5^(1/8) )^256 is

Binomial Expansion | Fractional Exponent.

Find the value of n in the binomial expansion of (1+3)^n. The coefficient of X^2 = 495

the coefficient of x³ in the expansion of (x-1/x)⁷ is | binomial theorem | jee mains Maths

Binomial Expansion with Negative exponent

二項展開を使用して二項を 4 乗展開します

Find The Coefficient Of x^5 In The Binomial Expansion Of (x-4)(3x+1)^6. Two binomials

The coefficient of x^48 in the expansion of (x-1)(x^2-2)(x^3-3)….(x^10-10) is (a)13(b)1(c) 25 (d) 31

Binomial Expansion wilth fractional exponent | lesson 2

Which term is independent of x, in the expansion of (x-1/(3x^2 ))^9|Binomial Theorem|RD Sharma|VSAQ

Find the coefficient of x^5 in the binomial expansion of (2x-8)^8

Find The Coefficient Of x^4 In The Binomial Expansion Of (x-3)(2x-1)^6. Two binomials

Expand ( x/3 + 1/x )^5 using binomial theorem for expansion

Coefficient of x^11 in the expansion of (1+x^2 )^4 (1+x^3 )^7 (1+x^4 )^12 is

In expansion of (1+x)^2n middle term is ((1.3.5...(2n-1))*2^n*x^n)/n! | Binomial Theorem

二項展開 (1-ax)^n の最初の 3 項が与えられ、指数と定数が求められます

The number of terms in the expansion of (1+x)^101 (1+x^2-x)^100 in powers of x is: