結果 : 1+tan^2 theta identity
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三角関数の恒等式を証明します: 1+tan^2 = sec^2

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Prove 1+tan^2theta=sec^2theta

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三角関数の恒等式 (sec(theta) - 1)(sec(theta) + 1) = tan^2(theta) を検証します。

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次の各等式を証明せよ: `(i) (1- tan^(2) theta)/(1+ tan^(2) theta)

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等式を証明してください: `(1+tan^2 theta) (1-sin theta) (1+sin theta) =1`

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