三角関数の恒等式を証明します: 1+tan^2 = sec^2
Prove 1+tan^2theta=sec^2theta
Prove: 1 + tan^2theta = sec^2theta | Trigonometric Identities | Class 10 Maths
Trig Identities
三角関数の恒等式 (sec(theta) - 1)(sec(theta) + 1) = tan^2(theta) を検証します。
次の各等式を証明せよ: `(i) (1- tan^(2) theta)/(1+ tan^(2) theta)
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Q52 | Prove that (1-tan^2θ)/(1+tan^2θ)=cos^2θ-sin^2θ | 1 - tan square theta by 1 + tan square
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等式を証明してください: `(1+tan^2 theta) (1-sin theta) (1+sin theta) =1`
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cos^2(1 + Tan^2) = 1