Binomial theorem SE11: Find the coefficient of x^7 in (1-x-x^2+x^3)^6 Binomial method

Multinomial theorem SE1: coefficient of x^8 in (1+x^2-x^3)^9

The term independent of x in expansion of ((x+1)/(x^(2/3)-x^(1/3)+1)-(x-1)/(x-x^(1/2) ))^10 is

The coefficient of x^48 in the expansion of (x-1)(x^2-2)(x^3-3)….(x^10-10) is (a)13(b)1(c) 25 (d) 31

Find the value of n in the binomial expansion of (1+3)^n. The coefficient of X^2 = 495

Binomial Expansion | Fractional Exponent.

The coefficient of xn in the expansion of is

二項展開（部分分数型） |試験ソリューション

級数の合計 1+x+x^2+x^3

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lim x→1 (x+x²+x³+....+xⁿ)-n /x-1

二項定理 : 分数累乗 : 展開 (1-2x)^1/3

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二項定理 変数 x に依存しない項を求める

式の x^99 の係数を求めます (x - 1) (x - 2) (x - 3) ...... (x - 100)

Find the coefficient of x^r in the expansion of 〖(x+3)〗^(n-1)+ (x+3)^(n-2) (x+2)+ 〖(x+3)〗^(n-3) 〖(x+

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The number of terms in the expansion of (1+x)^101 (1+x^2-x)^100 in powers of x is:

nth term of Binomial Expansion | General Formula