FOURIER SERIES: f(x)=1+(2x/pi) (x=-pi to 0) 1-(2x/pi) (x=0 to +pi) Deduce Π^2/8 = 1+1/3^2 + ...
Find the values of p and q for f(x)= (1-sin^3x)/3cos^2x,p,q(1-sinx)/(π-2x)^2 is continuous at x=π/2
なぜパイがここにいるのですか?そしてなぜ四角いのでしょうか?バーゼル問題に対する幾何学的な答え
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find values of p and q for which `f(x) = {(1-sin^3x)/(3cos^2x)` , if `x lt pi/2` and `p`...