Sum of n squares | explained visually |

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数学的帰納法を使用した合計公式の証明例 2

Prove by mathematical induction that the sum of squares of positive integers is n(n+1)(2n+1)/6

Prove the following by the principle of induction |1.3+3.5+5.7+..+(2n-1)(2n+1)=n(4n^+6n-)/3

導出 |式 |最初の n 個の正方形または平方数の合計 1^2 + 2^2 + 3^2 + 4^2 +...n^2

数学的帰納法: 1.3 + 3.5 + 5.7 ... + (2 n - 1)(2 n + 1) = n*(4*n^2 + 6n -1 ) / 3 を証明します。

Induction: Divisibility Proof example 1 (n³ + 3n² + 2n is divisible by 6)

誘導不等式の証明: 3^n は 2n + 1 以上です

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Prove by the principle of induction for all n belongs to N | 1^2 + 2^2 +...+ n^2 = n(n+1)(2n+1)/6

1.3+2.4+3.5+...+n(n+2)=n(n+1)(2n+7)/6 #数学的帰納法 #代数 L429

Prove that :`1^2+2^2+3^2++n^2=(n(n+1)(2n+1))/6`

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#22 Proof Principle of Mathematical induction mathgotserved 1^2+2^2 +3^2++ n^2 nn+12n+1 6

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Prove the following by the principle of induction | 1^2 + 3^2 + 5^2 +…..+ (2n-1)^2 = n(2n-1)(2n+1)/3