"Write the value of `cot^2theta-1/(sin^2theta)` ."
`(1+sin2θ-cos2θ)/(1+sin2θ+cos2θ)=tantheta`
Q20 | Prove that cot square theta - 1 by sin square theta = -1 | prove that cot^2θ - 1/sin^2θ = -1
`(2 sin theta*cos theta - cos theta)/(1-sin theta+sin^2 theta-cos^2 theta) = cot theta`
sin square theta + cos square theta = 1 How to prove?
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Prove that sin2θ/(1-cos2θ)=cotθ | sin 2 theta by 1 - cos 2 theta = cot theta
Prove: sin^2theta + cos^2theta = 1 | Trigonometric Identities | Class 10 Maths
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sin^2 θ+ cos^2 θ =1 | 1+ tan^2 θ =sec^2 θ | 1+cot^2 θ =cosec^2 θ Prove Trigonometric Identities
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`(1+sin 2theta+cos 2theta)/(1+sin2 theta-cos 2 theta)`=
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What is the value of `cot^(2) theta-1/(sin^(2) theta)`?