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tan(π/4+1/2 cos^-1a/b)+tan(π/4-1/2 cos^-1a/b)=2b/a l Inverse Trigonometry HOTS l CBSE-12th JEE
Evaluating Inverse Trigonometric Functions
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arctan(1/√3 tan x/2) = 1/2 arccos((1 + 2cos x)/(2 + cos x))
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tan(pi by 4 plus 1 by 2 cos inverse a by b) plus tan (pi by 4 minus 1 by 2 cos inverse a by b)
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Part 1: Exact Trig Values for Non Calculus