因数分解: - 2x^(4)-32 | 9 | 多項式の因数分解 | 数学 | S CHAND | ダウトナット

4^x=(2x)^32 | Math Olympiad Question

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Solve the equation for x : 4^2x = 1/32

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Q86 | If 4^2x=1/32, find the value of x

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2+2=4 4+4=8 Do you know what is 8+8

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Let f(x) = (2^(x+2)+16)/(2^(2x+1)+2^(x+4)+32) . Then the value of 8(f(1/15)+f(2/15)+⋯+f(59/15))

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