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Evaluate ∫(6x+5)root6-2x^2+x dx & ∫ (3x-2)root2x^2-x+1 dx 7M IMP (Q5,Q6)
グラフが放物線y=2x^2+3x-5を平行移動したもので、2点(2,-2)、(3,0)を通るような2次関数を求めよ。
3x + 5 = 2x + 13を解く
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Integral of (2x-3)/(2x^2-6x+5) (substitution)
Solve the Linear Equation 6x-5=2x+9, 6x-5=2x+9 solve the equation
`(2x-1)/3 -(6x-2)/5 =1/3`
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Solve `(5-2x)/3lt=x/6-5.`...
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