【数学】中3-27 二次方程式④(因数分解とのコラボ編)

2 つの方法で x^3+x^2+4=0 を解く

(x+3)(x+5) Expand and Simplify

因数分解を使用して方程式を解く、4x^2 - 5x + 1 = 0

3x^2 + 7x + 4 = 0

解決例 2: 不等式の 3 つのルール (x-1)^2(x-2)^3(x-3)^4(x-4)^5(x-5)^6 は 0 より大きい

The number of real roots of the equation 2 x^4+5 x^2+3=0, is 👇

3次関数の因数分解: kx 法

MP Board Class 10th Chapter 2: Polynomial, Exercise 2.2, Question 1 (Continue...)

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The number of real roots of the equation e^4x+e^3x–4e^2x+e^x+1=0 is __________

Exponential Equation | 2²ˣ⁺¹-9(2ˣ)+4=0

Jaldi Wahan Se Hato! IIT Delhi version! #iit #iitjee #iitdelhi

Solving a quadratic by completing the square

Maths Ki Problem 😜 PIHOOZZ

@btechmathshub7050Regula falsi メソッド x³-x-4=0

2(x-2)+3(4x-1)=0 || solve, 2(x-2)+3(4x-1)=0

Expand & Simplify: (2x - 3)(3x - 4)

maths tricks🔥| square root tricks | simplification tricks | #shorts #short #youtubeshorts

Solving Modulus Equations and Inequalities