5/x-1+1/y-2=2 6/x-1-3/y-2=1 Solve the following pairs of equations by reducing them to pair
`5/(x-1)+1/(y-2)=2` `6/(x-1)-3/(y-2)=1`
39 | 5/x-1+1/y-2=2 6/x-1 -3/y-2=1 | 5 upon X - 1 + 1 upon y - 2 = 2 6 upon X - 1 - 3 upon y - 2 = 1|
रैखिक समीकरण युग्म को हल कीजिए 5/(x-1)+1/(y-2)=2 6/(x-1)-3/(y-2)=1 | दो चर वाले रैखिक समीकरण युग्म
3+6 divided by 2 = 6??
5/x-2+1/y-2=2,6/x-1-3/y-2=1 समीकरण को प्रतिस्थापन विधि से हल करें ||5÷x-1+1÷y-2 =2,6÷x-1-3÷y-2=1
それらを一対の線形方程式 5/(x-1) + 1/(y-2) = 2 に還元して解きます。 6/(x-1) - 3/(y-2) = 1
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5/x-1 + 1/y-2=2,6/x-1 - 3/y-2=1 || Ncert Book 10th class प्रश्नावली 3.6 Questionnumber 1(IV)
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