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三角関数の最大 〜sinとcosの2次式〜
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Prove that sin^8 x−cos^8 x=(sin^2 x−cos^2 x)(1−2sin^2 xcos^2 x)
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22. Prove that (sin8 θ – cos8 θ) = (sin2 θ – cos2 θ) (1 – 2 sin2 θ cos2 θ)
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