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微積分ヘルプ: 積分 ∫ 1/(x^2 √(x^2-25)) dx - 三角関数の置換による積分
Integral 1/(x^2sqrt(25-x^2))
Integral of 1/(x^2+25) (substitution)
12年生 – 1/sqrt(9 - 25 x^2) dxの積分 | 積分 | チュートリアルポイント
#NCERT Class-XII Solution | Exercise 7.2 Q25 | #cbseclass12 | #Board_Exam | #Integration
Calculus Help: Integral ∫ dx/(x√(9x^2-25)) - Integration by trigonometric substitution
antiderivative of 1/(x^2sqrt(25-x^2)) using trig sub in 4 minutes
Integral of 1/sqrt(1-x^2)
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Integrate the function ∫ 1/root over 9-25x^2 dx
integrate sqrt(25 - x^2) (-2x)dx
Integral of 1 / sqrt(1-25^x)
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Integral of Sqrt(x^2 + 25) by Trigonometric Substitution | Integration | Calculus | Glass of Numbers
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