`cos(2sin^(- 1)x)=1-2x^2`

微積分学入門 - 三角法：三角関数の等式（57問中30問）証明 sin^2(x)=(1-cos2x)/2

why sin(2x)=2sin(x)cos(x)

show that (i) sin-1(2x√(1-x^2))=2sin-1 x and (ii) sin-1(2x√(1-x^2))=2cos-1 x

cos 2x = 1 - 2sin^2 x

逆三角関数の導関数 sin-1(2x)、cos-1 (x^2)、tan-1 (x/2) sec-1 (1+x^2)

Find the value of tan inverse 2 cos 2 sin inverse 1 by 2

tan 1 by 2 ( sin inverse 2x by 1+x square + cos inverse 1-y² by 1+y² )

Ex2.2 13. tan1/2 sin^(- 1)(2x)/(1+x^2)+cos^(- 1)(1-y^2)/(1+y^2) 12th math exercise 2.2 question13

cos^2x - sin^2x = 1 - 2sin^2x を証明する方法

Prove that `2sin^(- 1)x=sin^(- 1)[2xsqrt(1-x^2)]`

Prove that 2tan-1x = sin-1(2x/(1 + x2)) = cos-1((1 - x2)/(1 + x2)) ||ch2 12th properties 6

prove that 2cos^-1(x)=cos^-1(2x^2-1)

tan 1 by 2 (sin inverse 2x by 1+x square + cos inverse 1-y^2 by 1+y^2)

`tan[1/2(sin^(- 1)((2x)/(1+x^2))+cos^(- 1)((1-y^2)/(1+y^2))]` ||

Prove that 1+cosx=2cos^2(x/2) and 1-cosx=2sin^2(x/2) trigonometric identites

solve: `cos(2sin^-1x)=1/9`

1 - cos x = 2sin^2(x/2)

`"tan"1/2["sin"^(-1)(2x)/(1+x^(2))+"cos"^(-1)(1-y^(2))/(1+y^(2))]` |Class 12 MATH | Doubtnut

Find int (2 + sin 2x) e^x /(1 + cos 2x) dx | Integral (2+ sin2x/1+cos2x)e^x solution #integrals