cot 1 2 tan inverse alpha cot inverse alpha（関連順）

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'tan(alpha)+2tan(2alpha)+4tan(4alpha)+8cot(8alpha)=cot(alpha)' || tanx+2tan2x+4tan4x ||

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If the sum of all the solutions of tan^-1(2x/1-x^2) + cot^-1(1-x^2/2x) =pi/3 ,-1\le x\le 1,x\ne 0,is

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cot(tan^(-1)a+cot^(-1)a) | the value of cot(tan inverse a + cot inverse a) |

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The value of tan `alpha +2tan(2alpha)+4tan(4alpha)+...+2^(n-1)tan(2^(n-1)alpha)+2^ncot(2^nalp

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〖cot〗^(-1) [〖(cosα)〗^(1/2) ]-〖tan〗^(-1) [〖(cosα)〗^(1/2) ]=x, then sin⁡〖x=〗

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`cot^(-1)(sqrt(cosalpha)) - tan^(-1)(sqrt(cos alpha)) = x` の場合、`sin x` の値は

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重要 1 2 と 3 の Tan 逆関数の合計が 180 であることを証明する arctan(1) + arctan(2) + arctan(3) = 180

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3,322 回視聴 - 8 年前

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यदि `cot^(-1)(sqrt(cosalpha)) - tan^(-1)(sqrt(cos alpha)) = x`, तब tan x का मान होगा

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164 回視聴 - 5 年前

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`((1+sin2alpha)/(cos(2alpha-2pi)tan(alpha-(3pi)/4)))-1/4sin2alpha(cot(alpha/2)+cot((3pi)/2+alph...

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もし `(cot alpha+cot(270^(@)+alpha))/(cot alpha-cot(270^(@)+alpha))-2

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If `tanalpha + cotalpha= a`, then the value of `tan^4 alpha +cot^4 alpha ` is equal to

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if `cot^(-1)[sqrt(cosalpha)]-tan^(-1)[sqrt(cosalpha)]=x` then `sinx` is equal to

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結果 : cot 1 2 tan inverse alpha cot inverse alpha