結果 : cot 3 pi by 2 x
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'cos(3pi2 + x) cos(2pi + x )[ cot(3pi2- x) + cot(2pi + x)] = 1'||

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Prove that: `cos((3pi)/2+x)cos(2x+x)[cot((3pi)/2-x)+cot(2pi+x)]=1`...

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cos.((3pi)/2+x)cos.(2pi+x) [ cot((3pi)/2-x)+cot(2pi+x)]=1 | 11 | 三角関数 | 数学 |...

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`cos((3π)/(2) +x) cos(2π+x)[cot(3π)/(2)-x+cot(2π+x)]=1`

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Prove that : sec (3π/2 - x) sec(x - 5π/2) + tan(5π/2 + x) tan((x - 3π/2) = -1

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9. Prove that cos (3pi/2 + x) cos (2pi + x) { cot (3pi/2 - x) + cot (2 pi +x)} =1

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Cot(pi/20) Cot(3 pi/20) Cot(5 pi/20) Cot(7 pi/20) Cot(9 pi/20) = 1 @EAG

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次を証明してください: `cos((3pi)/2+x)cos(2x+x)[cot((3pi)/2-x)+cot(2pi+x)]=1`...

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`(cos^3(pi/2+x)cot(3pi+x)sec(x-3pi)c o s e c((3pi)/2-x)/(tan^2(x-pi)sin(x-2pi)`

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cos (3 pi/2+ x).cos(2pi +x).((cot 3pi/2 -x) + (cot 2pi + x))= 1

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9. cos(3π/2+x) cos⁡(2π+x) [cot⁡(3π/2-x)+cot⁡(2π+x) ]=1

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