cot a 2 formula in triangle（関連順）

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Show that in a triangle ABC, cot(A/2) + cot(B/2) + cot(C/2) = cot(A/2)*cot(B/2)*cot(C/2)

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In a triangle `ABC` if `cot(A/2)cot(B/2)=c, cot(B/2)cot(C/2)=a ` and `cot(C/2)cot(A/2)=b` then

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結果 : cot a 2 formula in triangle