Partial derivatives - Laplace equation

directional derivative phi = x^2 - y^2 + 2z point P(1,2,3) straight line PQ where Q point (5,0,4)

Problems on Partial Differentiation- U=log(x^2+y^2+z^2) , U=tan^-1(2xy/x^2-y^2), Z=f(x+ay) +Q(x-ay).

Find the minimum value of x^2+y^2+z^2 subject to the condition xyz=a^3

#Triple_Integral_problem_volume_of_the_ellipsoid_𝒙^𝟐/𝒂^𝟐 +𝒚^𝟐/𝒃^𝟐 +𝒛^𝟐/𝒄^𝟐 =𝟏

If u=f(r) where r2=x2+y2+z2 then dx2d2u​+dy2d2u​+dz2d2u​=f"(r)+r4​f′(r) partial differentiation

(2,-1,2)におけるx^2+y^2+z^2=9とz=x^2+y^2-3の面の間の角度を求めよ。

Find the minimum value of x^2+y^2+z^2 given that ax+by+cz=p

Find the minimum value of x^2 + y^2 + z^2 subject to the condition 1/x + 1/y + 1/z = 1 | Tamil

Derivatives: How To Calculate The Directional Derivative Of A Function.

ST x^2Ƙ^2u/x^2+y^2̘^2u/̘y^2+2xy^2u/̘x̘y =n(n-1)z オイラー偏微分 z 均一度 - 次

Solve: x(y²-z²)p+y(z²-x²)q=z(x²-y²) in Tamil MA3351 Transforms and Partial Differential Equations

ラグランジュ乗数を使用した f(x,y,z) の最大値と最小値

簡略化: (x^2+y^2-z^2)^2-\\ \\ (x^2-y^2+z^2)^2 | 9 | 代数的恒等式 | 数学 | RD SHARMA E...

Find the directional derivative of x²yz+4xz² at (1,-2,-1) in the direction of 2 i - j -2 k .#vector

u=x^2tan^-1(y/x) - y^2tan^-1(x/y)の場合、 θ^2u/θxθy= (x^2-y^2)/(x^2+ を証明します。 y^2) 偏導関数

problem, Directional Derivatives

Find the derivative of F = x^2-y^2+2z^2 at p(1,2,1) in the direction of PQ where Q =(5,0,4)

Partial Differentiation with Composite Function Problem #1 - Engineering Mathematics

VTUM2|Find the directional derivative engineering mathematics-Vector calculus