結果 : derivative of 2cos 2 theta
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y = cos(2 theta), Find the first and second derivatives of the function.

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consider `f_n(theta)=(2costheta-1)(2cos2theta-1)(2cos(2^2 theta)-1).....(2cos(2^n theta)-1)` th...

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differentiate 2^(cos²x) w.r.t. (cos²x), derivative of one function w.r.t. another

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If x = (2cosθ - cos2θ), y = (2sinθ - sin2θ) then Find d²y/dx² , θ = π/2

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(2cos theta + 1)(2cos theta - 1)(2cos 2theta - 1) = 2cos 4theta + 1

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Convert r^2cos(2theta)=1 to Cartesian

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Q5 | Find dy/dx , x = cos theta - cos 2 theta , y = sin theta - sin 2 theta

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