結果 : derivative of 2x^3-6x
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Find the derivative of y = 2x^3 + 6x^2 - 1

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Find the derivative of f(x) = [(2x^1/3-6x^5/3)^3][(4x^2-5x)^1/3]

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f(x) = 3/(2x)^3 + 3sin(6x) - 10 を微分します。

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Class: 12 Solve: (2x -3)(6x -1)(3x -2)(x -2) -5 = 0 TN TB Eg: 3.24

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`2x^(3) - 6x + 5` is an increasing function, if

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MA3151/ Y=2X3+3X2-36X, FIND INTERVALS OF INCREASE,DEC,LOCAL MAX(MINIMA),CONCAVITY, INFLECTION POINTS

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Find the Derivative of f(x) = (x^3 - 6x^2 + 8)/x^2

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December 7, 2024

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Find local Minimum and Maximum || y=2x^3-3x^2-36x+10 || part 2 ||

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`x=2^(1/3)-2^(-1/3)` then find `2x^3+6x`

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Q125 | Differentiate (3x^2+6x+5)^(7/2)

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