Derivative of 〖sec〗^(-1) {1/(〖2x〗^2-1)} w.r.t √(1+3x) at x=-1/3 is | DIFFERENTIATION
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Find dy/dx if y = sec⁻¹(1/2x²-1) differentiation inverse trigonometry ncert problems
逆三角関数: tan⁻¹ x + tan⁻¹ [2x/(1-x^2)] = tan⁻¹ [(3x-x^2)/(1-3x^2)] であることを証明してください。
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y = sec^-1 ( 1 / (2x^2 - 1) ) Find dy/dx | NCERT | CalculusCheck | Class12
The derivative of `sec^(-1)((1)/(2x^(2)-1))` with respect to `sqrt(1-x^(2))" at "x=1`, is
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