Equation of a tangent line to a curve, x^2+4xy+y^2=13, at point (2,1)
For x^2 + y^2 =13, find the slope of the tangent line at the point (-2,3)
Find equation of tangent line with implicit differentiation for x^2 + 2xy - y^2 + x = 2. At (1, 2)
e combined equation of the bisectors of the a (x2 + y2) 13 = 4xy is the bisectors of the angle ...
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3y^4 - 4y^2 + 7 - (-5y^4 - 6y^2 - 13) use a vertical format to subtract the polynomials
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"If `x^2+4y^2=4x y ,\ t h e n\ x : y`is`1:1`b. `1:2`c. `2:1`d. `1:4`"
Solve the differential equation (x² - 4xy - 2y²)dx + (y² - 4xy - 2x²)dy = 0 with solution |