Differentiation from first principle y=x^(3/2)+4x^2+3

Derivative dy/dx | Calculus problem.

第一原理による微分 - 例 2。

Chain Rule Steps to Differentiate y = (x^2 + 5)^3

Derivatives - Differentiation - Find dy/dx if y = x³ - 4x² + 6x - 7

Differentiate the function y = (x^2 + 4x + 3)/sqrt(x)

指数関数の微分

Sketch the graph of y= x^2+4x+3 #class11 curve sketching

Equation of tangent and normal to the curve

x に関して微分します: y=(4x^3-3x^2)/(4x^5-4)

Find the derivative dy/dx using chain rule for y = x^3 (2x -5)^4

Derivative of (3x+4)/(2x+5) || Quotient Rule of Differentiation

`y=(4x^3-5x^2+1)^4` , Find `(dy)/(dx)`.

23. Differentiate the function. y=(x^2+4x+3)/√x

Differentiate root (x-3) (x^2+4) / 3x^2 + 4x + 5 || Example 27 chapter 5 class 12 math ncert books

Differentiate w.r.t. x (2x^(3/2)-3x^(4/3)-5)^(5/2)

Derivatives - Differentiation - Find the derivative of y = (x² + 1) / (2x + 3)

How to differentiate f(x)=x^2 - 4x from first principle

デリバティブの解決例 |関数 y = (x⁴ + 4)(x² - 3) の導関数を求めます。

Differentiate the function. y = x^2+4x+3/√(x)