differentiation of 20/x^2-4（関連順）

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The potential at a point x due to some charges situated on the axis is given by V(x)= 20/(x 2-4)

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One factor of x^4+x^2-20 is x^2+5. The other factor is (a) x^2-4 (b) x-4 (c) x^2-5 (d) x+4

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結果 : differentiation of 20/x^2-4