If ` y=log (cosec x -cotx) ,then (dy)/(dx) `
Find the derivatives w.r.t. x : `log("cosec"x+cotx)`
Q34 | Differentiate log(cosecx-cotx) | Derivative of log(cosecx-cotx) | log cosec x - cot x
DIFFERENTIATION OF y= log (cosecx - cotx) in tamil /CBSE BOARD /12TH CLASS
`log("cosec x"-cot x)`
Find the derivatives of : `cot x" w.r.t. cosec"x`
`cosec x cot x`
How to differentiate y=ln(cosecx), Chain Rule version
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y = 1/[ {cosecx + cotx}^1/3]. Find dy/dx | Differentiation | Calculus Check
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Q4 | Differentiate logx w. r. t. cotx | Differentiate log x with respect to cot x | Class 12
Differentiate the following functions w.r.t. x : `cosec x * cot x `