y = tan^-1{(3x - x^3)/ (1-3x^2)} Find dy/dx | Differentiation | CalculusCheck | NCERT

|| Evaluate integral tan inverse of (3x-x^3)/(1-3x^2).dx ||in Telugu|| engineering mathematics 2||

Find dy/dx if y = tan^-1(3x-x³/1-3x²) | Differentiate of tan inverse 3x minus x cube by 1 minus 3x

tan-1[(3x-x^3)/(1-3x^2)] | Inverse function | Derivation

Mastering Calculus: Derivative of Inverse Tangent Function [𝑡𝑎𝑛^(−1) ((3𝑥−𝑥^3)/(1−3𝑥^2 ))] Explained

Prove the following: tan^(-1)x+tan^(-1)((2x)/(1-x^2))=tan^(-1)((3x-x^3)/(1-3x^2)) | CLASS 12 | I...

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Example 7 Show that tan-1 x + tan-1 2x/(1 −x2) = tan-1 (3x − x3)/(1 − 3x2) 

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