Find the derivative dy/dx using chain rule for y = 3/(sqrt(2x +1)).

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Find the derivative dy/dx using chain rule for y = x^3 (2x -5)^4

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Differentiate w.r.t. x `(2x+1)^3`

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If f(x) = 2x^2 - 3x + 5, find f(x+1).

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If `y=[3x+2][2x-1]`, then find `(dy)/(dx)`.

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Take the derivative of the natural log function