結果 : differentiation of y=x^2 - 4x
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Differentiation from first principle y=x^(3/2)+4x^2+3

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DERIVATIVE FROM FIRST PRINCIPLES: Point For Tangent To y = x^2 - 4x - 5 Is Parallel To 2x - y = 1

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y = x^2 - 4x - 5, y = 0, between x = -1 and x = 4

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OCR MEI Core 1 3.07 y = x^2 + 4x - 21 のグラフをもう一度描きます

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find dy/dx,if x^2+y^2+4x+6y+1=0|differentiation

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OCR MEI Core 1 3.04 y = x^2 - 4x + 4 のグラフを描きます

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Find the derivative of y=x^2+4x at x=-5

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A curve has equation y=x^3+2x^2-4x+6 show that dy/dx=0 when x=-2 and x=2/3. Find value of d^2y/dx^2

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How to differentiate f(x)=x^2 - 4x from first principle

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Sketch and find area of region bounded by graph of y = x^2 -4x +3, x=0, y =0. Definite Integral

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Derivatives - Differentiation - Find dy/dx if y = x³ - 4x² + 6x - 7

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Plot the graph y = x^2 - 4x - 5

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Chain Rule Steps to Differentiate y = (x^2 + 5)^3

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Implicit Differentiation

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MCV4U Example 6 from 4.050 Graph y = (x^2 - 4x - 1)/(x - 1)

Jim Beland
144 回視聴 - 5 年前
4:43

The area of the region enclosed by the curves y = x^2 - 4x + 4 and y^2 = 16 - 8x is :

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340 回視聴 - 5 か月前
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Step to draw y=x^2-4x+1and find solution to quadratic equation y=x^2-5x+4

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12,441 回視聴 - 6 年前
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Find the derivative dy/dx using chain rule for y = x^3 (2x -5)^4

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