結果 : equation of tangent to the parabola y^(2)=4ax at p(at2) 2at) is

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4:50

点 (at², 2at) における放物線 y²= 4ax の接線と法線の方程式を求めます。

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The tangent to the parabola `y^(2)=4ax` at `P(at_(1)^(2), 2at_(1))" and Q"(at_(2)^(2), 2at_(2))`

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2:15

パラメトリック方程式 x=at2 y=2at が放物線の方程式 y2=4ax | を表すことを示します。ピタゴラス数学

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The tangent PT and normal PN of parabola y^2=4ax at a point P on it meets the x axis at T and N.

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The tangent PT and the normal PN to the parabola y2=4ax at a point P on it meet its axis at points T

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Equation of Tangent to the parabola y² = 4ax at a point (x1,y1)

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