結果 : evaluate integral 2+sin2x/1+cos2x
5:07

次の積分を評価します: `inte^(x)((2-sin2x)/(1-cos2x))dx`

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`inte^x(2-sin2x)/(1-cos2x)& dd; x`

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`int(sin2x)/((1-cos2x)(2-cos2x))dx=`

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微積分ヘルプ: e^2x (1-sin2x)/(1-cos2x) dx の積分 - 部分積分

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