evaluate integral x 1 x 2 4x 5 dx（関連順）

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Evaluate the Integral (x+4)/(x^2 +2x +5) dx.

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integrate '1/4throot((x-1)^3(x+2)^5) dx' || Evaluate: int1/(root(4)((x-1)^3 (x+2)^5)\ dx .

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x=0 から 1 までの (2x^4 - 3x^2 + 5) dx の定積分を求めます。

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結果 : evaluate integral x 1 x 2 4x 5 dx