Evaluate `int((x+3))/(sqrt(5-4x-x^(2)))dx`.

integrate (x+3)/sqrt(5-4x+x^2) dx || `int[x+3]/sqrt[5-4x-x^2].dx`

Find the following integrals: `int(x+3)/(sqrt(5-4x+x^2))dx`...

`int[x+3]/sqrt[5-4x-x^2].dx`

`int(x+3)/(sqrt(5-4x-x^2))dx`

`(x+3)/(sqrt(5-4x-x^2))`

微積分ヘルプ: ∫ (x+3)/√(5-4x-x^2 ) dx の積分 - 三角関数の置換による積分

int(x+3)/sqrt(5-4x-x^2) dx | 12 | 不定積分 | 数学 | KC SINHA | ダウトナット

(i) `(x+3)/sqrt(5-4x-x^(2)) dx` का मान ज्ञात कीजिए।

integrate (x + 3)/(sqrt(5 - 4x - x ^ 2)) dx को ज्ञात करें |

Evaluate the integral of x^2 sqrt(4x+5) dx from 0 to 1

Evaluate: `int(x^3+5x^2+4x+1)/(x^2)\\ dx`

微積分：∫√(5+4x-x^2)dxの積分 - sqrt(5+4x-x^2)の積分 - 三角関数の置換

Evaluate the Integral (x+4)/(x^2 +2x +5) dx.

(x-2)/(x^2-4x+5) の積分 - 積分の例

置換を用いた不定積分: Int(2x^4*sqrt(5+3x^5),x)

Calculus Help: Integral of (2x+3)/√(5+4x-x^2 ) dx - Integration by substitution

微積分ヘルプ: 積分 ∫ dx/(5-4x-x^2 )^2 - 三角関数の置換による積分

Proof that √2 is irrational #maths #squareroot #shorts #justmathwithme

Calculus Help: Integral ∫ x^2/√(5-4x^2 ) dx - Integration by trigonometric substitution