3x^3-2x^2-12x+8=0の解き方
Find the absolute maximum and minimum value of f on [-2,3]. F(x) = 2x^3 - 3x^2- 12x +1
The function `f(x)=2x^3-3x^2-12x+4` has
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x = 0 における曲線 y = 2x³ - 3x² - 12x + 8 の勾配を求めます。
Find intervals where f(x) = 3x^4 - 4x^3 - 12x^2 +5 are increasing, decreasing. Local Max, Min
For f=X^3 -12x +2 find intervals of increase decrease, max min and test concavity. Sketch graph
積と連鎖則を使用して 2 つの二項式の導関数を取得する
Find points on the curve y= 2x^3 + 3x^2 -12x + 1 where the tangent is horizontal
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If the polynomial x4+2x3+8x2+12x+18 is divided by another polynomial x2+5 the remainder comes out to