x3-3x2-9x-5 factorise | how to factorise x3-3x2-9x-5 | factorise x3-3x2-9x-5 by factor theorem
Factorise x3-3x2-9x-5| | Factorise x cube -3xsquare-9x-5 ||Factorise x3-3x2-9x-5 By Factor Theorem |
`x^(3)-3x^(2)-9x-5`を因数分解します。
Factorise x3 – 3x2 – 9x – 5
因数分解: (i) `x^3-2x^2-x+2` (ii) `x^3-3x^2-9x-5` (iii) `x^3+13 x^2+32 x+20` (iv) `2y^3+y^2-2y-1`
#find the factors of x^3-3x^2-9x-5
Factorize x3-3x2-9x-5, Factorise x3-3x2-9x-5
Factorise x3-3x2-9x-5 | Factorise x Cube Minus 3 x Square - 9 x Minus 5 | Factorise x^3-3x^2-9x-5
Factorise x³-3x²-9x-5
Factoring x^3+5x^2+3x-9
Factorise x^3-2x^2-x+2 I x^3-3x^2-9x-5 I x^3+13^2+32x+20 I 2y^3+y^2-2y-1 I
Solve `x^3-3x^2-9x-5` | Class 12 Maths | Doubtnut
Factorize : x^3 – 3x^2 – 9x – 5#mathsclass9
Using factor theorem, factorize of the polynomials: x^3 – 3x^2 – 9x – 5
Factorise : `x^3-3x^2-9x-5`. | Class 11 Maths | Doubtnut
Factorise: (i) `x^3-2x^2-x+2` (ii) `x^3-3x^2-9x-5` (iii) `x^3+13 x^2+32 x+20` (iv) `2y^3+y^2-2y-...
3 次多項式の因数分解 - 代数 2 と微積分前
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x^3-3x^2-9x-5 | を因数分解します。多項式 |例 2.4 クラス 9 [Q5 (ii)]
Polynomials Class 9th Ex 2.3 Q5(ii) Factorise x3 - 3x2 - 9x - 5 | Factorisation by Factor Theorem