Find the derivative of the function: f(x) = (2x^2-3x) (-4x^-2+5)
Differentiation (First Principles): 9. Derivative of f(x)=3x^2+2x+5
Find the derivative of `f(x)=2x^2+3x-5` at `x=-1`. Also, prove that `f'(0)+3f'(-1)=0.`
第一原理による微分 - 例 2。
Find the derivative of the function `f(x)=2x^2+3x-5` at `x = 1` . Also prove that `f^(prime)(0)+...
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Example 6 find the derivative of the function f(x)=2x^2+3x-5 at x=-1 then prove that f'(0)+3f'(-1)=0
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If f(x) = 2x^2 - 3x + 5, find f(x+1).
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f(x)=2x^2+3x-5 の x=-1 における導関数を求めなさい。また、f\'(0)+3f\'(-1)=0 であることを証明しなさい。 | クラス 11 | ...
y = (2x+5)/(3x-2), find the derivative
If `f(x)=2x^(2)+3x-5,` then what is `f\'(0)+3f\'(-1)` equal to?
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