Find dy/dx if y = tan^-1(3x-x³/1-3x²) | Differentiate of tan inverse 3x minus x cube by 1 minus 3x
Differentiate y=tan^-1(3x-x^3/1-3x^2)
y=`tan^(-1)((3x-x^(3))/(1-3x^(2)))`Find dy/dx
14. Derivative Find dy by dx of y = tan -1( 3x-x3 upon 1-3x2)
tan-1[(3x-x^3)/(1-3x^2)] | Inverse function | Derivation
tan^-1[(3x-x^3)/(1-3x^2)],find dy/dx@Mathby1069
#shortsvideo #tan^-1(x+3)+tan^-1(x-3)=tan^-1(4/39)
Differentiate `tan^(-1)((3x-x^3)/(1-3x^2)),if` `-1/sqrt(3)ltxlt1 /sqrt(3)`(2)`xgt1/sqrt(3)``( 3...
次のことを証明してください: tan^(-1)x+tan^(-1)((2x)/(1-x^2))=tan^(-1)((3x-x^3)/(1-3x^2)) | クラス 12 | I...
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