Find the slope of the tangent of the curve (i) `y = (x^(3) -x) " at " x = 2` (ii) `y =

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Find the slope of the tangent to the curve y = x^3 – x at x = 2.

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The slope of the tangent to the curve `y=-x^(3)+3x^(2)+9x-27` is maximum when `x` equals

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微積分ヘルプ: 与えられた点における曲線の傾きを求めよ: (1;4) では y=3+2x-x^2、(2;8) では y=x^3

Find the slope of the tangent to the curve y = x^3 ​–3x + 2 at the point whose x-coordinate is 3.

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At what points, the slope of the curve `y=-x^3+3x^2+9x-27` at point `(x ,\\ \\ y)` is given by m...