How to Prove (1+cos pi/8)(1+cos(3pi)/8)(1+cos(5pi)/8)(1+cos(7pi)/8)=1/8 Trigonometry CBSE JEE NDA

Find the value of (1+cos π/8)(1+cos 3π/8)(1+cos 5π/8)(1+cos 7π/8) #iitjee #maths

show that the values of (1+sinπ/8+icosπ/8/1+sinπ/8-icosπ/8)^8/3 || maths 2a regular question

(1+cos π/8)(1+cos 3π/8)(1+cos 5π/8)(1+cos 7π/8)=

Show that one value of1+Sin(pie/8)+icos(pie/8) 1+Sin(pie/8)-icos(pie/8).

Show that one value of [(1+sin⁡〖π/8〗+ⅈ cos⁡〖π/8〗)/(1+sin⁡〖π/8〗-ⅈ cos⁡〖π/8〗 )]^(8/3) ⅈs-1 #iit jee

`(1+cos.(pi)/(8))(1+cos.(3pi)/(8))(1+cos.(5pi)/(8))(1+cos.(7pi)/(8))` is equal to

[IIT 1984] Find the value of [1+cos(PI/8)]*[1+cos(3*PI/8)]*[1+cos(5*PI/8)]*[1+cos(7*PI/8)].

Application of Integrals : All Concept & PYQs Covered | Class 12th Boards | NCERT @Xylemplustwo

`(1+cos. ( pi)/(8))(1+ cos. ( 3pi)/(8)) ( 1+ cos. ( 5pi)/(8)) ( 1+ cos. ( 7pi)/(8))=`

Show that one value of { (1+ sin pi/8 + i cos pi/8) / (1+ sin pi/8 - i cos pi/8) }^(8/3) = -1

cos(pi/8)

Prove that: (1 - cos(Pi/8)) (1 - cos(3Pi/8)) (1 - cos(5Pi/8)) (1 - cos(7Pi/8)) = 1/8

(1 + Sin pi/8 + i Cos pi/8 / 1 + Sin pi/8 – i Cos pi/8)⁸/³ = – 1 : Dead easy solution @EAG

Finding the Value of (1 + cos(π/8))(1 + cos(3π/8))(1 + cos(5π/8))(1 + cos(7π/8))"#maths

`(1+cos(pi/8))(1+cos(3pi/8))(1+cos(5pi/8))(1+cos(7(pi)/8))=`

find the value of cos(pi/8) | cos(π/8) | cos(22.5°)

Find the values of `cospi/8`

Show that [1 + Sin (π/8) + i Cos (π/8) by 1 + Sin (π/8) - i Cos (π/8) ]^ (8/3) = -1

prove that (1+cos π/8)(1+cos 3π/8)(1+cos 5π/8)(1+cos 7π/8) =1/8