Integral of 6/sqrt(16-x^2)
三角関数の置換積分 sqrt(x^2 - 16)/x
微積分ヘルプ: ∫ x^2/√(16-x^2 ) dx の積分 - 三角関数置換による積分 - 解決済み!
integral of 1/sqrt(16-x^2) dx
Integration of Rational Functions By Completing The Square - Calculus
微積分ヘルプ: ∫√(16-x^2)dx の積分 - 三角関数の置換による積分
Calculus: Integrating sqrt(16-16x^2) from 0 to 1, using substitution x = Sinθ
Integral of 16/sqrt(16 - x^2)
integral of 1/sqrt(x^2+16)
Integrate | 1/sqrt(16-x^2) dx
(integration by substitution) integral of x^2/sqrt(16-x^2)
How to solve integral 1/sqrt(16-x^2) sin^-1 (x/2) dx with u sub.
Calculus Help: Integral of (x^3 dx)/√(16-x^2 ) - Integration by substitution
(3x^2)sqrt(16 - x^6)の積分
(6x^2)/sqrt(16 - x^6)の積分
Integral 42: int 1/[x^2 sqrt(16 x^2)} dx
Integral of 1/sqrt(16 - x^2) dx using trigonometric substitution
微積分ヘルプ: dx/(x√(x^2-16)) の積分 - 置換積分
Integral of (x + 5)/sqrt(16 - (x - 4)^2) using Inverse Sine
微積分ヘルプ: 積分 ∫ √(25-16x^2 )/x dx - 三角関数の置換による積分