Find `int(3x-2)/((x+1)^2(x+3)dx`...
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x=-1 から 2 までの定積分 (3x^2 - 2x + 3)dx を計算します。
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∫_0^1▒ (2x^3-3x^2-x+1)^(1/3) dxの値は、(1) 0(2) 1(3) 2(4) -1に等しい。
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Hasil dari integral (3x^2+2x+3) dx adalah ...
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