`int(dx)/(sqrt(1-9x^(2)))`
`int(1)/(sqrt(1-9x^(2)))dx`の値を求めます。
評価: `int(1)/(sqrt(1-9x^(2))) \" dx \"`
Calculus Help: Integral ∫ dx/(x√(9x^2-25)) - Integration by trigonometric substitution
Integral of sqrt(1-9x^2) dx [Calculus 2]
整数 1/sqrt(1+9*x^2) に三角置換を適用します。 x=(1/3)tan(θ) として、接線恒等式を適用します。
微積分ヘルプ: dx/√(9x^2-1) の積分 - 三角関数の置換による積分
Integral 1/sqrt(4-9x^2)
Integral of sqrt(1+4x²)^1/2
微積分ヘルプ: dx/√(1-9x^2) の積分 - 三角関数の置換による積分
積分 (12) (1+9x^2)
Evaluate the Integral 1/(9x^2 -16) dx. Partial Fraction Decomposition. Integrate
#Find integral ∫ 1/sqrt(16- 9x^2 ) dx.
Integral Practice #94: integral of (sqrt(1 + sqrt(x)))dx
Integral of 1/sqrt(9 - x^2) dx using trigonometric substitution
Integration of 3/1+9x^2 dx
`int(dx)/(sqrt(9x-4x^2))` equals (A) `1/9sin^(-1)((9x-8)/8)+C` (B) `1/2sin^(-1)((8x-9)/9)+C` (C)...
∫(1 - √(1 - x²)) dx [-1, 1] = ? Integration problem with answer by area under curve.
Integral of 1/(4 + 9x^2)^2 dx by using trigonometric substitution
How to integrate 1/sqrt(16 9x^2), indefinite integral, integration by substitution, calculus
