結果 : integral of 1/root(x^2 =16)
8:38

integral of 1/sqrt(x^2+16)

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integral of 1/sqrt(16-x^2) dx

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Integrate the function ∫ 1/root over 16x^2+25 dx

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三角関数の置換積分 sqrt(x^2 - 16)/x

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Part 153 Integration of 1/√(16-6x-x²)dx, 1/√(7-6x-x²)dx, 1/√(5x²-2x)dx

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157 回視聴 - 2 年前
5:55

Evaluate the following integrals: ∫√(16 x^2+25) d x

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`int(dx)/(sqrt(16-x^(2)))`

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Integration Of DX/x2-16 #shorts #susmitasharmaclasses #bbmkuuniversity

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Integrate the function ∫ 1/x^2-16 dx

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😳 CLEAN BASIC CALCULUS Integrate ∫1/1+x^2 dx=? #Shorts

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