Integral of (1/(sqrt(x^2 – 6x))
クラス 12 – 1/sqrt(-x^2 - 6x + 7) の積分 |積分 |チュートリアルのポイント
問題 U5 27 | 1 / sqrt(x^2 - 6x +13) の積分
Integral sqrt(x^2-6x+8)
dx/sqrt(x^2 - 6x) の積分 (三角関数の代入 -- Trig Sub #7!)
Integral of 1/sqrt(x^2 - 6x + 10)
Integral of 1/(x^2-6x+18) (substitution)
Integral of 2/sqrt(x^2 - 6x) dx by using trigonometric substitution
Integration of 1/x^2-6x+9 dx
Integrate the functions `1/(sqrt(7-6x-x^2)`...
integrate 1/sqrt(9x^2 + 6x - 8) dx
Integral of 1/(x^2+6x+10) (substitution)
Calculus: Integration of 1/(x-3)sqrt(x^2-6x+8). Simple and easy!
Trig Substitution: Integral x/sqrt(x^2-6x+8)
Integration of Rational Functions By Completing The Square - Calculus
Integral dx/[sqrt(x^2-6x+13)]
`(1)/(sqrt(7-6x-x^(2)))`
Calculus Help: ∫ (2x-1)/√(x^2-6x+18) dx - Integration by trigonometric substitution
Integral of 1/sqrt(a^2-x^2) (substitution)
integral of 1 / x² + 6x + 12 dx
