Integral of 1/sqrt(-x^2+6x -5)dx

`int ((1)/((6x-5)^(4))-(1)/((8-3x)^(9)))dx=`

1/(5～6x)の積分

Integral of sqrt(x^6 - 6x^5 + 9x^4 + 2x^3 - 6x^2 + 1)

Integrate 1/(9x^2 + 6x +5) // Integration by substitution // समाकलन // प्रतिस्थापन विधि

微積分ヘルプ: 積分 - 基本 - ∫ (3x^2-4x^3+6x-5+1/√(x^4 ))dx - テクニック

∫6x+5.sqrt 6-2x^2+x dx

Integral 1/(9x^2+6x+5) || integral Integral 1/(9x^2+6x+5)

∫1/√(x² + x) dx = ? Solve without using substitution method.

Integration (Calculus)

Evaluate ∫(6x+5)root6-2x^2+x dx & ∫ (3x-2)root2x^2-x+1 dx 7M IMP (Q5,Q6)

∫2ˣx² dx = ?? MIT Integration Bee 2024, Regular Season, Problem 17. #mitintegrationbee #integral

【高校数学】今週の積分#79【難易度★★★】

`int(6x-5)/(sqrt(3x^2-5x+1))dx`

微積分ヘルプ: 積分 ∫ (x+1)/(3x^2+6x-5) dx - 置換積分 - テクニック

1/(sin^6(x)+cos^6(x)) の積分

∫4t³dt [6, f(x)] = (x-2)g(x), f(2)=6, f’(2) = 1/48. Find lim x →2 g(x). JEE-Main India, 12 /4/2021.

∫(e^(x + eˣ) - e^(x - eˣ)) dx. MIT Integration Bee 2019 (Question 3, qualifying exam).

integration of 6x-5/sqrt3x^2-5x+1

∫e^(-1/x)/x² dx [0, ∞] = ??