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指数関数の置換積分 - 原始微分 - 微積分
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Gaussian Integral [Int{e^-x^2} from -inf to inf]
It "Cannot" Be Done (Integrals)
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If tan[theta/2]=√1−e/1+e tan[phi/2] then prove that cosϕ=costheta−e/1−ecodtheta
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Integral of exp(-x^2) | MIT 18.02SC Multivariable Calculus, Fall 2010
Is the derivative of e^2x this simple? #shorts
このガウス積分に円周率 (π) が含まれるのはなぜですか?
how Laplace solved the Gaussian integral