微積分ヘルプ: dx/√(3-2x-x^2) の積分 - 三角関数の置換による積分
Calculus Help: Integral ∫ √(3-2x) x^2 dx - Integration by substitution - 置換積分
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dx/(sqrt(3+2x-x^2)) を積分するか、1/(3+2x-x^2)^(1 /2) dx を積分します。
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微積分ヘルプ: (2x^2+4x-3)/x^2 dx の積分を求めよ
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