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integral '0 to pi/2', 'cos^2x/cos^2x+4 sin^2x' || Integral of cos^2x / ( cos^2x + 4sin^2x) ||

integral 0 to pi/2 cos^2(x) dx || integral 0 to pi/2 cos^2(x) dx ||

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Find the integral of x*sin2x*sin [(PI/2)*cosx ] / (2x - PI) between the limits 0 and PI.

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Visualizing Differentiation of Sin(x^2)#maths#shorts#gcse #integration#mathematics #science#stem